Maximum height formula straight up I've managed to work through the following: Looking at this I believe it is a conservation of energy problem. 81 = 0. What maximum height above its launch point does the ball attain? What is the acceleration of the projectile when it reaches its maximum height? A ball is thrown straight up with an initial speed of 30 m/s. 0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9. 0 \ m/s and it strikes the ground with a velocity of 31. Step-by-Step Guidance: Utilizing the Height Calculator Experience the simplicity of our tool with straightforward instructions. The formula is h=v²/(2g). Oct 11, 2024 · Apply the formula h = v 0 2 sin 2 (θ) / (2g), where g is the acceleration due to gravity. The distance between initial point and final point in a straight line ( shortest distance). The maximum height a projectile reaches above its release point is \({H_{\max }} = \frac{{{u^2}{{\sin }^2}\theta }}{{2g}}\). Sep 14, 2023 · Given the initial velocity of a baseball thrown from a given height, we compute the range of the ball and the maximum height of the ball using projectile mot May 26, 2023 · How do you find the maximum height of a ball thrown straight up? Use the vertical motion model, h = -16t2 + vt + s where v is the initial velocity in feet/second and s is the height in feet, to calculate the maximum height of the ball. 8 /5 A ball is thrown straight upward. For maximum height, we know θ = 90°. Revision. 5 meters above its starting point. It's not affected by what's happening in the x direction. Two balls are launched straight up into the air. Oct 29, 2024 · Calculate the time required to reach the maximum height: it corresponds to the time at which vᵧ = 0, and it is equal to t = vᵧ/g = 3. What is the maximum height, h in meters, the ball reaches? What is the work done by gravity, Wg in Joules, during the ball's flight to its maximum height? Jul 30, 2024 · 2. If you use the vertical component of its initial speed, you can write. The formula to calculate the maximum height \(h\) of a projectile is given by: \[ h = \frac{V₀² \sin(α)²}{2g} \] where: \(V₀\) is the initial velocity of the projectile (in meters per second), \(α\) is the launch angle relative to the horizontal (in degrees), Learn how to calculate the height of a projectile given the time in this Khan Academy physics tutorial. (Assume negligible air resistance. In other words, the vertical velocity equals zero for a moment. Jun 21, 2023 · How does the angle of projection affect the maximum height? The angle of projection (\( \theta \)) significantly affects the maximum height. My question was where did the $\frac{-b}{2a}$ came from. 8m/s^2 * 35m) = √686m^2/s^2 = 26. Jul 19, 2019 · Consider that when heigt is 35 meters, the velocity is zero. 81 m/s^2. #underbrace(v_"h max"^2)_(color(blue)("=0")) = v_text(0y)^2 - 2 * g * h_"max"# This is equivalent to Nov 22, 2024 · Maximum height depends on initial vertical velocity and is reached when vertical velocity becomes zero. Projectile Motion Formula Sheet: https://bit. When will the projectile's height be half of its maximum height? a. Its altitude height h after t seconds is given by ht=-16t2+64t . If a ball is thrown vertically upward from the roof of 32-ft building with a velocity of 48 ft/sec, its height (in ft) after t seconds is s(t) = 32+48t -16t^2. Historical Background Aug 27, 2007 · An angle of 90 degrees (straight up) will result in the maximum height of the object. Jun 10, 2024 · Time of maximum height is the time when the object attains the maximum height and is given by t=usinθg. 0 m/s {/eq}. The height is maximized when the angle is 90 degrees (i. 4N, Homework Equations A spring-loaded toy dart is used to shoot a dart straight up in the air, and the dart reaches a maximum height of 16 m. Mar 27, 2006 · To find the height of an object thrown straight up, you can use the formula h = v 2 / 2g, where h is the height, v is the initial velocity, and g is the acceleration due to gravity. Use the formula (0 – V) / -32. May 23, 2022 · Step 1/2 1. Its speed at half the maximum height that it can reach is 16 m/s. (a) What are the interacting objects and how do they interact? Feb 24, 2023 · A tennis ball of mass m = 0. e. 79 m above its launch point, the ball's speed is one-half its launch speed. Solved. Maximum height of a projectile: The maximum height of a projectile is given by the formula H = u sin θ 2 2 g, where u is the initial velocity, θ is the angle at which the object is thrown and g is the acceleration due to gravity. 540 m,what is its initial speed as it leaves the ground? (b) How long is itin the air? . A projectile is thrown with a velocity vat an angle a with horizontal. At what height is the speed of the ball equal to half of its initial value? Assume that the ball starts at a height; A ball is thrown straight up and rises to a maximum height of 24 m above the ground. This concept is rooted in the principles of kinematics and the conservation of energy. 525 m . 11. Jan 28, 2024 · A batter hits a baseball straight upward at home plate and the ball is caught 5. ) Choose upward as the (+) direction and set the ground at y = 0. Link to This lecture is about deriving the maximum height of the projectile motion and how to calculate the maximum height of the projectile motion. Maximum Projectile Height Formula. Share . In your case the time at which the ball reaches the maximum height is t = = 4 seconds. A tennis player hits a $58. 41 m (B) 41 m (C) 410 m (D) 4. Apr 17, 2023 · "Consider a hypothetical dense astronomical object with a mass of $2 × 10^{30}$ kg (about the mass of the sun), and a radius of $1. 327 s. (a) Find the height of the ball when t = 1 sec and when t = 1/2 sec. we can ignore airt resistance. Factors that influenc the height of these objects include the height from which the objects are dropped or thrown, whether upward/downward velocity is involved, and of course, the pull of gravity downward on the object. maximum height formula straight up max height ball thrown straight up how to find max height of a ball thrown straight up calculate max height of ball thrown a boy in the building at height 10m sees the ball travelling at speed 10m/s. An object that is launched straight up from the ground reaches maximum height H and falls straight back down to the ground, hitting it T seconds after launch. How do you calculate the projectile's maximum height using a calculator? Students should enter projectile motion parameters such as initial height, angle of launch, and initial velocity into the relevant input sections of the Maximum height calculator. 8 m/s^2). First, we need to determine the initial velocity of the softball when it was thrown straight up. We want to find the maximum height of the jump. The most straightforward method (Mid-Parental height formula) is based on parents' height only. When is the object's displacement 0? An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 43, where ''t'' is in seconds, from a height of 30 feet. You will need to measure the initial velocity and use a timer to determine the time it takes for the object to reach its highest point. Understand each component's impact on the maximum height achieved by the projectile. Motion along x is irrelevant! A baseball is thrown straight upward on the Moon with an initial speed of $35 \mathrm{~m} / \mathrm{s}$. 0 s after it is struck Figure \(\PageIndex{3}\). 8 m/s^2), and t is the time it takes for the softball to reach the maximum height. (a) If a flea can jump straight up to a height of 0. Conversely, if you know the initial angle and maximum height, the calculator can find the initial velocity, travel distance, and flight duration. -4 ± square root of 2 b. How do you find the time to maximum height? Determine the time it takes for the projectile to reach its maximum height. The question relates position and velocity, so you want to use equation 3. Projectile motion involves objects that are dropped, thrown straight up, or thrown straight down. It turns out that the instantaneous velocity of the water balloon is given by \(v(t) = -32t + 16\text{,}\) where \(v\) is measured in feet per second and \(t\) is measured in seconds. Popularity 5/10 Helpfulness 1/10 Language whatever. Aug 4, 2021 · A baseball is thrown straight upward on the Moon with an initial speed of $35 \mathrm{~m} / \mathrm{s}$. 80 m/s , and an angle of 87. 5m We can use here the general relationship from kinematics: color(red)(v_f^2=v_i^2+2a(y_f-y_i)) where: v_i is the initial velocity=15m/s; v_f is the final felocity which is zero in our case; a is the acceleraton of gravity g=-9. A 0. 2 m . After doing research on my own and from the answer that was given I figured out that it was related to the equation of the parabola which can be derived from its general f Sep 28, 2023 · How to solve maximum height projectile motion problems using 5 easy steps. Find… You throw an object straight up such that it leaves your hand with a… Q. Maximum height is the position at which y-velocity is zero. At 3. It can also work 'in reverse'. 9 m/s. 2 ft/s^2 = T where V is the initial vertical velocity found in step 2. 0 \mathrm{~g}$ tennis ball so that it goes straight up and reaches a maximum height of $6. h (1) = h (1/2) = ft ft (b) Find the maximum height of the ball and the time at which that height is attained. The small part hits the ground 7 seconds later. 2 ± square root of 2 d. Range depends on both initial horizontal velocity and time of flight. Nov 12, 2007 · Homework Statement A 0. 5 m T = U/g = 49/9. Putting the values in the formula we get, h = (5 x sin90°)/ (2x10) [sin 90° = 1] h = 1. 8 m/s2 v = v o + a t = v o – g t May 18, 2023 · 3. -2+ square root of 2 An object is thrown straight up with a velocity, in ft/s, given by v(t) = -32t + 47, where t is in seconds, from a height of 24 feet. The highest point in any trajectory, the maximum height, is reached when v y = 0 v y = 0; this is the moment when the vertical velocity switches from positive (upwards) to negative (downwards). Jul 21, 2015 · The projectile will decelerate on its way to maximum height, come to a complete stop at maximum height, then starts its free fall descent towards the ground. To acquire the maximum height as an output in a fraction of a second, press the calculate 📌 The formula for maximum height is derived by substituting t_y_max into the equation for vertical displacement (y). The goal of this problem is to find the maximum height she attains and her speed at half the maximum height. y o = 0 , v o = +10 m/s a = – g = –9. y=v22a Solve for v. 00:00 Maximum height criteria02:14 Example & solutionSupport the channel (hey it be Note that because up is positive, the initial vertical velocity is positive, as is the maximum height, but the acceleration resulting from gravity is negative. Answer: The water droplets leaving the hose can be treated as projectiles, and so the maximum height can be found using the formula: The maximum height of the water from the hose is 50. Assuming you could stand on the surface of this object, if you fired a gun straight into the air, how high above the surface would the bullet go before turning around? At the maximum: t max = v y (0)/g. 4 ± square root of 2 C. See an example of a cannonball shot straight up and how to calculate its displacement, velocity, and acceleration. (a) What is the initial velocity of the ball? (b) What is the maximum height the ball reaches? (c) How long does it take to reach the maximum height? (d) What is the acceleration at the top of its path? Find the max height the mass will travel up the incline. Assumption: 35 m is the maximum height from the ground, else, if the maximum heigth from the ground is 35 m + 1 m = 36 m, the numbers are: A {eq}\displaystyle 60. Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67. Dec 14, 2017 · $\begingroup$ @scott I understood the vertex is the maximum height and of course I have seen the graph. The vertex for A 60. Launch from an elevation (initial height > 0) In that case, the time spent flying upwards is shorter than the time when the object is falling down. A kangaroo jumps straight up with an initial vertical velocity of 2. As soon as the projectile reaches its maximum height, its upward movement stops and it starts to fall. t = u / a. Tags: formula height whatever. 21 × 0. 23 kg ball of dough is thrown straight up into the air with an initial velocity of 12 m/s. 17 \mathrm{~m} . 0 \ m/s. 6-m/s initial vertical component of velocity reaches a maximum height of 233 m (neglecting air resistance). The you can use the formula for free fall with initial velocity zero. The same dart is shot straight up a second time from the same gun, but this time the spring is compressed only half as far before firing. The maximum height is reached when \(\mathrm{v_y=0}\). For example, if you know the initial velocity and angle, the calculator can determine the flight duration, maximum height, and travel distance of the projectile. Part of a playlist on 2D kinematics and pro Jun 22, 2021 · A flare was launched straight up from the ground with an initial velocity of 176ft/s and returned to the ground after 11 s. Use the vertical motion model, h = -16t2 + vt + s where v is the initial velocity in feet/second and s is the height in feet, to calculate the maximum height of the ball. But bullets from rifles firing standard cartridges or from handguns are capable of reaching significant heights. Motion along x is irrelevant! The maximum height reached by a ball thrown straight up into the air can be determined by the formula \(h = -16t^2 + vt + d\), where t is the number of seconds since it was thrown, v is the initial speed of the throw (in feet per second), d is the height (in feet) at which the ball was released, and h is the height of ball t seconds after the throw. 4 ms. Describe the velocity vs. In this case, you want to find the starting velocity that gives a maximum height of 3. Sep 9, 2022 · Graph the motion of an object which is thrown upward, then use the kinematic equations to find the maximum height the ball reaches as well as the total time A student with a third floor dormitory window 32 feet off the ground tosses a water balloon straight up in the air with an initial velocity of 16 feet per second. Thus v_y(t) = v sin theta - g t , the vertical velocity as a function of time. Know about the time of flight formula, horizontal range, maximum height, the equation of trajectory along with examples. 8)=122. Now the moment of maximum height happens when the object stops rising - when v_y(t)=0. Find a) the time taken to reach the maximum height; b) the maximum height with respect to the ground next to the A box is dropped vertically downward from a window. For other angles, the maximum height is reduced according to the \( \sin^2(\theta) \) term in the formula \( H Apr 10, 2018 · The formula gives the maximum height y of a projectile launched straight up, given acceleration a and initial velocity v. Substitute the values in the equation: y = 3. A baseball is thrown straight up, and its height as a function of time is given by the formula h = − 16 t 2 + 32 t (where h is in feet and t is in seconds). Ignoring air; A 1-kg rocket is fired straight up from level ground. Sep 16, 2024 · This physics video tutorial explains how to find the maximum height and range quickly using direct formulas. ] (A) 0. 81 × (0. 0 m above the cliff. $ How much work does gravity do on the ball on the way up? Example: Projectile Motion: A projectile is fired straight up from the ground with an initial speed of |v o | = 10 m/s. May 7, 2023 · How do you find the maximum height of an object thrown straight up? You throw a ball into the air from a height of 5 feet with an initial vertical velocity of 32 feet per second. The maximum height is determined by: (i) the initial velocity in the y-direction, and (ii) the acceleration due to gravity. This example is of a ball that is thrown up and then comes back down. Jul 26, 2024 · The maximum height calculator is a tool for finding the maximum vertical position of a launched object in projectile motion. At the maximum: t max = v y (0)/g. Substitute into y(t) = v y (0) t - ½ g t 2 to give y max = v y (0) 2 / 2g. 0-kg {/eq} athlete leaps straight up into the air from a trampoline with an initial speed of {eq}\displaystyle 9. Apr 16, 2016 · I found 11. The equation is h(t)=-16t^2+32t, which forms a parabola that opens down. 1 m The work done on a slingshot is $40. Vf = √(2gh) = √(2*9. A frictional force of 9. (Avoid this pitfall: The velocity at the highest point in projectile motion is not zero, although the vertical component of As the first human astronaut to land on a distant planet, you are standing on the edge of a small cliff. 2 m/s. May 16, 2023 · If we know the initial velocity with which the ball is thrown vertically upward (u), then by using the formula H max = u 2 /2g, we can easily find out the maximum height of the ball thrown vertically upward. 7 m/s. Mar 15, 2017 · Physics Ninja looks at the kinematics of projectile motion. 25 m. Scalar quantity. 4 × 10^{14}$ m. 4N acts on the block as it moves up the incline. The one we provide here (the Khamis-Roche Formula) is proven to be the most accurate without the use of skeletal age. Assume that the ball starts at a height; A ball is thrown straight up and rises to a maximum height of 21 m above the ground. Type Range (ft) Interpretation; Hopping Hares: 0 – 5: Leap like a bunny, but not too high! Soaring Seagulls: 6 – 50: Spread your wings and take flight! Jul 30, 2024 · Maximum height: h m a x = h + V y 0 2 / (2 g) h_\mathrm{max} = h + V^2_ \mathrm{y0} / (2 g) h max = h + V y0 2 / (2 g) Using our projectile motion calculator will surely save you a lot of time. The maximum height for a rocket is calculated after it runs out of fuel. , the ball is thrown straight up). Let the gravitational potential energy be zero at the initial height of the tennis ball. 4°. 8 = 5 sec. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is Nov 5, 2020 · Maximum Height. Mar 26, 2016 · Learn how to use the equation for the cannonball's highest point, where its vertical velocity will be zero, to find the maximum height of a projectile. The height in feet of a bullet fired straight up is given by {eq}h= 1280t -16t^2 {/eq}, where {eq}t {/eq} is in seconds. For example, enter the time of flight, distance, and initial height, and watch it do all the calculations for you! Jul 28, 2022 · y max = y 0 + V 0 2 sin 2 α/(2g) where: y 0 — Initial height or vertical position; V 0y — Initial vertical velocity; V 0 — Initial total velocity (called initial velocity in the maximum height calculator); g — Gravity acceleration; α — Angle of launch; and; y max — Calculated maximum height; And that's it! That's the maximum May 15, 2023 · A ball thrown vertically upward reaches a certain height and comes down… What is the acceleration of the ball at its maximum height? How to find the maximum height of a ball thrown up? An object is thrown vertically upward and returns after 10 seconds. From the displacement equation we can Apr 7, 2017 · A ball is thrown vertically upwards with a velocity of 49m/s calculate the maximum height and time taken to reach maximum height. Neglect any effects due to air resistance. 00:01 Hello students in this question we have a ball which is thrown straight upward with the speed u it is equals to 30 meter per second in the up direction okay air resistance is negligible so for the part a we have to determine the time taken by the ball to reach the maximum height so at the maximum height the final speed we will be equals to zero so v this is equal to u minus g multiplied Visualise projectile motion in an interesting way. 0 m/s. Since we know the initial velocity, initial position, and the value of v y when the firework reaches its maximum height, we use the following equation to find y y Example: a ball, thrown vertically up with a speed of 25 km/h, can reach a maximum height of almost 2. 327 - 9. If the ball rises to a maximum height of 3. Distance, d Displacement, 𝖔⃗ Length of actual path between two points. What maximum vertical height, h, will the block reach? m = 5. 7 m, how much kinetic energy was dissipated by the drag force of air resistan; A tennis ball (m = 56 g) is projected vertically with an initial speed of 8. a) Find the momentum of the ball of dough at its maximum height. The green ball has an initial velocity twice as large as the red ball's initial velocity. 3 days ago · The faster a projectile is thrown up, the longer it will stay in the air. 2) An athlete in a high jump competition leaves the ground at a velocity of 5. Calculate the maximum height it reaches in meters. This is especially true for rifles firing magnum cartridges. calculate the maximum height and time taken to reach maximum height. To get the maximum height value, substitute t= 4 seconds into the formula s(4) = -16*4^2 + 128*4 + 4 = 260 feet. v=2ay‾‾‾‾√ v=4y2a2 v=4a2y2 v=2ay√a star 4. I calculate the maximum height and the range of the projectile motion. A ball is thrown vertically upward with a velocity of 20 m/s. You toss a small experiment apparatus straight up in the air and it reaches a maximum height of 3. 075 kg is thrown straight up with an initial speed v0 = 11 m/s. We can use the formula: v_f = v_i + at where v_f is the final velocity (which is zero at the maximum height), v_i is the initial velocity, a is the acceleration due to gravity (-9. b) You are asked how long (time) it takes the ball to reach the ground (position), so you want to use equation 1. 0$ joules to pull back a 0. Compute $(a)$ the maximum height reached by the ball, $(b)$ the time taken to reach that height, $(c)$ its velocity $30 \mathrm{~s}$ after it is thrown, and $(d)$ when the ball's height is $100 \mathrm{~m}$. The maximum height is determined solely by the initial velocity in the y direction and the acceleration due to gravity. Dec 15, 2010 · The maximum height reached by a thrown object can be calculated using the following formula: h = (v^2 * sin^2θ) / 2g, where h is the maximum height, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9. What is its momentum at its maximum height? Homework Equations momentum=mass X velocity change in momentum= mass Oct 3, 2024 · The formula for the maximum height of a projectile motion is a fundamental concept in physics, particularly useful in sports like basketball where it helps in analyzing the peak height of a ball thrown at an angle. Compute $(a)$ the maximum height reached by the ball, (b) the time taken to reach that height, $(c)$ its velocity $30 \mathrm{~s}$ after it is thrown, and $(d)$ when the ball's height is $100 \mathrm{~m}$. A ball is thrown straight up with no air resistance. If a ball is thrown straight up with an initial velocity of v feet per second, it will reach a maximum height of H = v 2 / 64 H=v^{2} / 64 H = v 2 /64 feet. See examples of projectiles with different initial velocities and angles of projection. Source: Grepper. 21 / 9. (a) Express the average speed over the entire trip as a function of H and T. The acceleration due to gravity is 9. Maximum Height. Use g = 10 m/s2. Find the momentum of the ball of dough halfway to its maximum height on the way up. Whether you need the max height formula for an object starting directly off the ground or from some initial elevation – we've got you covered. Take up as positive. A projectile is fired straight up with a velocity of 64 ft/s. The question is broken into two time intervals, and simple kinematic equations are May 30, 2018 · The relevant piece of information is the initial vertical velocity - when t=0, v_y=v sin theta, and so v sin theta = C - g*0 = C. 8 m, how much kinetic energy was dissipated by the drag force of air resistance? We compute the maximum height and velocity at the top of the trajectory for a projectile launched from the ground. What is the maximum height the bullet will reach? The message also states the flight time of the bullet to reach the maximum height. Some use mathematical estimations as a base and are entirely safe (because the child is not exposed to any hazardous factors). Three seconds after lift off, a small part of the rocket falls off the side. Find and interpret the sensitivity of the height to the initial velocity when the initial velocity is 40 ft/sec. Learn how to calculate the maximum height of a projectile using the formula H = (v0)2sin2θ 2×g. 10kilogram stone. Time of flight is determined by initial vertical velocity and is independent of horizontal velocity. Using this we can rearrange the velocity equation to find the time it will take for the object to reach maximum height \[\mathrm{t_h=\dfrac{u⋅\sin θ}{g}}\] where \(\mathrm{t_h}\) stands for the time it takes to reach maximum height. Bullets can reach great heights if fired straight up or nearly straight up. 8m/s^2 (downward); y_f is the height reached from the ground where y_i=0. 3 m. 0kg, vi = 11m/s, vf = 0m/s, Fr = 9. The height of the flare t seconds after launch is modeled by the function f(t)=-16t^2+176t What is the maximum height of the flare, in feet? Aug 28, 2021 · maximum height formula straight up max height ball thrown straight up how to find max height of a ball thrown straight up calculate max height of ball thrown a boy in the building at height 10m sees the ball travelling at speed 10m/s. 15 kg ball of dough is thrown straight up into the air with an initial speed of 5. Aug 11, 2021 · Note also that the maximum height depends only on the vertical component of the initial velocity, so that any projectile with a 67. If the box was released with a velocity of 6. The formula for the projectile range is the same: the horizontal velocity (V₀) multiplied by the time of flight equation (launching from an initial height):. ∴ The maximum height will be 1. The apparatus then falls to the bottom of the cliff, landing a distance of 10 m below its initial position. We know, v 2 = u 2 - 2gh In this chapter, we will deal with kinematics only and will concentrate on the simplest kind of motion – a body moving along a straight-line path. Is the formula for calculating maximum height only applicable to objects thrown upward? Yes, the formula for calculating maximum height is specifically for objects thrown upward against the force of gravity. a) What is the maximum height above the ground obtained by the; A rocket is launched straight up with a constant acceleration. 🔢 The final formula for maximum height is given by: h_max = (V₀^2 * sin^2(θ)) / (2 * g), where V₀ is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. Projectile Motion Nov 6, 2016 · Homework Statement A 5. 0. Alternate Method: The maximum height can alternatively be found with the help of the equations of motion as the bag is thrown vertically upwards. Learn how to use multiple methods to calculate the maximum height of a projectile and see examples that walk through sample problems step-by-step for you to improve your physics knowledge and skills. 15kg ball of dough is thrown straight up into the air with an initial speed of 17 m/s. Which kinematic formula would be most useful to solve for the target unknown? If the slingshot projects the stone straight up in the air, what is the maximum height to which the stone will rise? [Neglect friction. This means that the object’s vertical velocity shifts from positive to negative. maximum height formula straight up Comment . 0kg block initally traveling at 11m/s moves up a 30degrees incline. H = U 2 /(2g) = (49 2)/(2 x 9. 327)² /2 = 0. time. A baseball is thrown straight up, and its height as a function of time is given by the formula h = − 16 t 2 + 32 t h=-16 t^2+32 t h = − 16 t 2 + 32 t (where h h h is in feet and t t t is in seconds). Therefore, if vy – g * t(vy=0) = 0, you can modify the formula to t(vy=0) = vy / g. ----- Notice that the formula you posted is FATALLY WRONG: It works ONLY when the height s(t) measures in FEET, not in meters. Sep 2, 2019 · Maximum Height of Projectile Using CalculusWe find the velocity, the maximum height, and the speed of a projectile using calculus. lsbn susgoj fde gbcc owodkqd gydsrn roohknx hwmix synpv pffaly